4.7 / 10 Actionthri... -

limx→af(x)=0 and limx→ag(x)=0limit over x right arrow a of f of x equals 0 and limit over x right arrow a of g of x equals 0

, can have a determined limit for their ratio based on their slopes (derivatives) at that point. ✅ Result 4.7 / 10 ActionThri...

: First, evaluate the limit directly. If it yields 000 over 0 end-fraction limx→af(x)=0 and limx→ag(x)=0limit over x right arrow a

limx→af(x)=±∞ and limx→ag(x)=±∞limit over x right arrow a of f of x equals plus or minus infinity and limit over x right arrow a of g of x equals plus or minus infinity 4.7 / 10 ActionThri...

limx→af(x)g(x)=limx→af′(x)g′(x)limit over x right arrow a of f of x over g of x end-fraction equals limit over x right arrow a of f prime of x over g prime of x end-fraction provided the limit on the right exists (or is ±∞plus or minus infinity Step-by-Step Application

∞∞the fraction with numerator infinity and denominator infinity end-fraction Feature Overview: L'Hôpital's Rule